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From O, draw OM perpendicular to AB. We know that the perpendicular from the centre of a circle to a chord bisects the chord. ∴ BM = (162) cm=8 cm

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... of the given circle with centre O. The perpendicular distance from the centre of the circle to the chord is 8 cm. Join OB. Then OM = 8 cm and AB = 30 cm

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